2.1 and 2.2 slides

Hello, friends!!
I'm very sorry to be late posting my slides that I used for presentation today..
It's because I didn't know how to upload the file on blogspot..
But, I found another way.

http://www.mediafire.com/view/?t1s9zdptjmusp9u

That link will  bring you to my slides. But, you need to download it first. I only uploaded Chapter 2.1 and 2.2 which I made.
I'm sorry. I don't have Farah's and Rachael's slides. But, Farah said she will upload the whole slides on her blog. So, maybe you guys can check out her blog..

Well, thank you very much guys!
Hope this slides can help you to study for the quiz tomorrow :)
Good luck to us!!!!

Long Division of Polynomials

Still confused using long division to divide polynomials? Watch this video! It's very useful.

I've watched this video too! :)

Synthetic Division

I've just found these videos. It's easier to understand by watching these videos how to divide polynomial functions by using Horner's method. Horner's method is same as Synthetic Division.

The Remainder Theorem

Last week, we started learning Chapter 2 about The Remainder Theorem. Actually, I kinda like this subchapter because I've learnt it in my high school. This subchapter is not that difficult. You just need to pay more attention while dividing and multiplying.  In my high school, besides using long division, we use Horner's method. What is Horner's method? We'll check it out. It's easier than using Long Division. But, I'm not sure whether you can use this method on test. Well, at least this method can help you with mutliple choice questions or just check your answer.

Divide x⁵ – 4x³ + 3 by x² – 2x – 3

1) Use Long Division 

2) Use Horner's Method

Quotient = x³ + 2x² + 3x + 12

Remainder      =    (x – b)R₂  + R₁

                         =    (x – 3)(33) + (138)

                         =    33x – 99 + 138

                         =    33x – 39

This is an example in the textbook Page 86. (Advanced Functions 12 McGraw-Hill Ryerson)
We'll try to solve the question by using Horner's Method.

The volume, V, in cubic centimetres, of a rectangular box is given by V(x) = x³ + 7x² + 14x + 8.
Determine expressions for possible dimensions of the box if the height, h, in centimetres, is given by x + 2.

Solution

Horner's Method

Q(x) = lw  = x² + 5x +4

                   = (x + 1)(x + 4)

P(x) = V = x³ + 7x² + 14x + 8

              = (x + 2)(x² + 5x +4)

Expressions for the possible dimensions of the box, in centimetres, are (x + 1), (x + 2), and (x + 4).